RF and Baseband Signal Conditioning
| Step | Technical Description | |
|---|---|---|
| 1 | The baseband bandwidth is defined by the product specifications and RF front-end signal design. | |
| 2 |
After the mixer, the baseband signal is conditioned by the LPF and PGA to limit the signal bandwidth, suppress out-of-band noise, and optimize the signal level before the ADC. |
|
| 3 | The ADC samples the conditioned baseband signal at a fixed sampling rate determined by the system (e.g., 2.5 MHz). |

1. Signal Flow and Processing
Step1. Given Condition
Allocated bandwidth: 200 MHz ← ISM Band 24.045 GHz ~ 24.245 GHz
Step2. Requirments by a customer
| Requirement | Symbol | Typical Value | Design Impact | |
| Max Range Limit | R_max | 8 m | R_max(Requirement)→B_BB(System Limit)→T_UP(Design variables) | |
| Range Resolution | ΔR | 0.75 m | Defines the RF chirp bandwidth, B_RF = c/2ΔR | |
| Max Velocity Limit | V_max | 25 m/s | Constrains the maximum allowable chirp cycle to avoid Doppler aliasing. | |
| Velocity Resolution | ΔV | 0.25 m/s | Defines the required CPI, i.e., the number of chirps per frame |
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Step3. Chirp Design
| Name | Symbol | Typical value | Description | |
| RF Chirp Bandwidth | B_RF | 200 MHz | Selected B_RF=200 MHz within allocated band | |
| Baseband Bandwidth | B_BB | 25.4 kHz | Fixed by system bandwidth limitation (ADC/LPF). | |
| Waveform | – | CW + SAW | Continuous-wave transmission with sawtooth FMCW chirp | |
| Start Time | T_START | 20 us | typically fixed, hardware-determined settling time | |
| Down-chirp Time | T_DOWN | 150 us | typically fixed, hardware-determined reset/return time | |
| Stop Time | T_STOP | 410 us | typically fixed, hardware-determined idle/guard time | |
| Up-chirp Time | T_UP(min) | 420 us | The actual value shall be determined by considering the frame structure. |
Step4. Chirp Design Result
| Name | Formula | Example Value | Description | |
| Chirp Cycle | 1,000 us | |||
| Chirp Slope | 0.476 MHz/µs | B_RF is defined by ΔR | ||
| Baseband Signal Bandwidth | 25.4kHz |
Step5. Frame Design

2. Example Cases
32 Chirps
T_CHIRP = 1,000 us = 1ms
T_PRE=20us
T_NOP=76uS
T_2PD=22uS
T_PD = T_NOP – 2 x T_2PD = 76 – 2*22 = 32us
Frame Cycle = T_PRE + N x T_CHIRP + T_NOP = 20 us + 32 x 1 ms + 76 us = 32.096 ms
Duty Ratio = [ T_FRAME / (T_FRAME+T_NOP) ] * 100 = [ 32.096 / (0.076+32.096) ] * 100 = 99.76 %


